I think I've worked with some form of all of these, except for Euler's polyhedra formula.
The only wrong thing I could find is that the lower integration limit on the Fourier transform should be negative infinity. And the Maxwell eqn's given here are for the specific case of in a vacuum.
As for Black-Scholes, it's a different form of differential equation than Schrodinger's, so the functions that are solutions to each are quite different.
- As for Black-Scholes, it's a different form of differential equation than Schrodinger's, so the functions that are solutions to each are quite different.
Both classify as parabolic when considered as time-dependent PDE, so there's a mutual similarity to the heat equation and its solutions.
Thanks for that, makes sense.
I must be forgetting why the Schrodinger eq'n is non-dispersive, like why there isn't some first order spatial derivative, similar to the second term of this form of Black-Scholes. I think it's some assumption baked into a particular physical situation. Closed boundary conditions or something, right? It's been too long.
Holy thread necromancy, Batman!
- why the Schrodinger eq'n is non-dispersive
That's because it preserves total probability even under time-evolution operator (norm conservation works in both cases). Evolution over imaginary axis (ih-bar) means that the energy is redistributed, but not lost, as solution phase-space is conserved. That's the same as being 'non-dissipative.'